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An urn contains 6 white b***s and 2 red b***s. A second urn contains 5 white b***s and 2 red b***s. A ball is drawn at random for each urn. Find the probability there are one of each.

 Mar 13, 2016
 #1
avatar+2499 
+5

An urn contains 6 white b***s and 2 red b***s. A second urn contains 5 white b***s and 2 red b***s. A ball is drawn at random for each urn. Find the probability there are one of each.

 

so what is the probability of geting white on the first one and red on the second:

(6/8)*(2/7) = 0.2142857142857143

 

and what is the probability of geting red on the first one and white on the second:

(2/8)*(5/7) = 0.2142857142857143

 

 

0.2142857142857143+0.1785714285714286 = 0.3928571428571429

 

Answer: 0.4 or 40%

 Mar 13, 2016
 #2
avatar+2499 
0

And welcome to the forum :)

there is another solution to that think about that if you wan t found ask i will wrote

Solveit  Mar 13, 2016

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