mm Hlpe

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mm Hlpe

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how to simplify (4 - 8x)(4 + 8x)

and also

factorise Fully

x^2-7x+12

4x^2-25

4x^2-13x+3

6x^3+3x^2+4x+2

Guest Oct 29, 2015

edited by Guest Oct 29, 2015
edited by Guest Oct 29, 2015
edited by Guest Oct 29, 2015
edited by Guest Oct 29, 2015
edited by Guest Oct 29, 2015

Best Answer

5⁺¹ Answers

#4

+12530

+5

The graph

Omi67 Oct 29, 2015

#5

+26396

+30

Best Answer

how to simplify (4 - 8x)(4 + 8x)

The right answer is:

$\begin{array}{rcl} (4 - 8x)(4 + 8x) &=& \\ &=&4^2 - (8x)^2\\ &=& 16 -64\cdot x^2\\\\ \mathbf{(4 - 8x)(4 + 8x) } & \mathbf{=} & \mathbf{16 -64\cdot x^2} \end{array}$

heureka Oct 29, 2015

2 Online Users

heureka · Answer 1 · 2015-10-29T09:16:47

how to simplify (4 - 8x)(4 + 8x)

The right answer is:

$\begin{array}{rcl} (4 - 8x)(4 + 8x) &=& \\ &=&4^2 - (8x)^2\\ &=& 16 -64\cdot x^2\\\\ \mathbf{(4 - 8x)(4 + 8x) } & \mathbf{=} & \mathbf{16 -64\cdot x^2} \end{array}$

Melody · Answer 2 · 2015-10-29T06:49:56

First you should learn how to expand double brackets.

So here is a good place to start.

https://www.youtube.com/watch?v=iB3L5csbB4E

Omi67 · Answer 3 · 2015-10-29T07:17:50

Hallo guest

Omi67 · Answer 4 · 2015-10-29T08:19:41

The last one: