2sec(x+60)=5sec(x-20)
2 /cos (x + 60) = 5 / cos ( x - 20)
2 / [ cosxcos60 - sinxsin60] = 5 / [ cosxcos20 + sinxsin20]
2 [ cosxcos20 + sinxsin20] = 5 [ cosxcos60 - sinxsin60]
2 [ cosx cos20 + sinxsin20] = 5 [ (cosx)/2 - (sqrt(3)*sinx) /2 ]
4[cosxcos20 + sinxsin20] = 5 [cosx - sqrt(3)*sinx]
sinx [ 4sin20 + 5sqrt(3)] = cosx [ 5 - 4cos20]
sinx / cosx = [ 5 - 4cos20] / [ 4sin20 + 5sqrt(3)]
tanx = [ 5 - 4cos20] / [ 4sin20 + 5sqrt(3)]
arctan ( [ 5 - 4cos20] / [ 4sin20 + 5sqrt(3)]) = x = about 7.056° + n*360° where n is an integer
Here's a graph : https://www.desmos.com/calculator/oqxckkdfx2
2sec(x+60)=5sec(x-20)
2⋅sec(x+60∘)=5⋅sec(x−20∘)We substitute x=y−20∘2⋅sec(y−20∘+60∘)=5⋅sec(y−20∘−20∘)2⋅sec(y+40∘)=5⋅sec(y−40∘)|sec(ϕ)=1cos(ϕ)2cos(y+40∘)=5cos(y−40∘)cos(y−40∘)cos(y+40∘)=52|cos(y−40∘)=cos(y)cos(40∘)+sin(y)sin(40∘)cos(y)cos(40∘)+sin(y)sin(40∘)cos(y+40∘)=52|cos(y+40∘)=cos(y)cos(40∘)−sin(y)sin(40∘)cos(y)cos(40∘)+sin(y)sin(40∘)cos(y)cos(40∘)cos(y)cos(40∘)−sin(y)sin(40∘)cos(y)cos(40∘)=521+tan(y)tan(40∘)1−tan(y)tan(40∘)=522⋅[ 1+tan(y)tan(40∘) ]=5⋅[ 1−tan(y)tan(40∘) ]2+2⋅tan(y)tan(40∘)=5−5⋅tan(y)tan(40∘)7⋅tan(y)tan(40∘)=3tan(y)=37⋅1tan(40∘)|y=x+20∘tan(x+20∘)=37⋅1tan(40∘)x+20∘=arctan(37⋅1tan(40∘))±n⋅180∘x=−20∘+arctan(37⋅1tan(40∘))±n⋅180∘x=−20∘+arctan(0.51075153968)±n⋅180∘x=−20∘+27.0557431286∘±n⋅180∘x=7.0557431286∘±n⋅180∘n∈N