math problem

(8-3^2)^6 + (2 x 3-7)^9=0

(8-3^2)^6 + (2 x 3-7)^9

$\small{ \begin{array}{rcl} (8-3^2)^6 + (2 \cdot 3-7)^9 \\ &=& (8-9)^6 + ( 6-7)^9\\ &=& (-1)^6 + (-1)^9 \\ &=& (-1)^6 [ 1 + (-1)^3] \qquad | \qquad [ 1 + (-1)^3] = [ 1 + (-1)(-1)(-1)]=[1-1]=0\\ &=& (-1)^6 \cdot 0 \\ (8-3^2)^6 + (2 \cdot 3-7)^9 &=& 0 \end{array} }$