Math help

Suppose you drop a ball from a window 40 meter above the ground.The ball bounces 70% of the previous height each bounce.What is the total number of meters the ball travels between the time it dropped and the tenth bounce?

geometric sequence
$a_1 = 40\ m \\ r = 70\ \% = 0.7$

$\begin{array}{rcll} s &=& a_1 \left( \frac{1-r^{11}}{1-r} \right) \\ s &=& 40 \left( \frac{1-0.7^{11}}{1-0.7} \right) \\ s &=& 40 \left( \frac{1-0.01977326743}{1-0.7} \right) \\ s &=& 40 \left( \frac{0.98022673257}{0.3} \right) \\ s &=& 40 \cdot 3.26742244190 \\ s &=& 130.696897676\ m \end{array}$

I get something a little different from heureka, here

It's dropped 40 m ......  and then the distance given by the geometric series  :

2 *28* [ 1 - .7^9] / [ 1 - .7]  

So....the total distance traveled  =

40 + 2*28 * [ 1 - .7^9] / [ 1 - .7]   =  219.13 m