+1124 make "p" the subject.
x=53−√2p−1
I did this:
35x=−√2p−1
(35x)2=−2p−1
(35x)2+1=−2p
925x2+1=−2p
3425x2=−2p
−12∗3425x2=p
−1725x2=p
Is this correct?...Thank you for your time...
+26399 make "p" the subject.
x=53−√2p−1
x=53−√2p−1|−53x−53=−√2p−1|×(−1)−x+53=√2p−153−x=√2p−1|square both sides(53−x)2=2p−1|+1(53−x)2+1=2p|:2(53−x)2+12=p
+1124 Heureka,
Thank you so much for the answer....how daft of me, to multiply the fraction instead of subtracting it...gosh..
..thank you kindly..
