log base 3(log base 8(log base 10(x))) = -1
(log((log((log(x))/(log(10))))/(log(8))))/(log(3)) = -1
log3 {log8[ log10(x) ] }=−1|u=log8[ log10(x) ]log3(u)=−13log3(u)=3−1u=13u=log8[ log10(x) ]=13|v=log10(x)log8(v)=138log8(v)=813v=813v=233v=2v=log10(x)=210log10(x)=102x=100