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Let f(x)={ax+3, if x>2,x5 if 2x2,2xb if x<2. Find a+b if the piecewise function is continuous (which means that its graph can be drawn without lifting your pencil from the paper).

 Aug 14, 2023
 #1
avatar+130458 
+1

Put 2 into  each of the  first two functions  for x and set them  equal

 

a(2) + 3 = 2 - 5

2a = 2 - 5 - 3

2a = -6

a = -3

 

Put - 2  into  each of the last two  functions for x and  set them equal

 

-2 - 5 = 2(-2) - b

-7 = -4 - b

b = -4 + 7

b = 3

 

a + b =  3 + -3  =   0

 

cool cool cool

 Aug 14, 2023
 #2
avatar+170 
+3

Rigorously, continuity is defined below:
 

For every k in the domain of f;

  • f(k) exists
  •  limikf(i) exists (i.e. limikf(i)=limik+f(i))
  • and limikf(i)=f(k)
 Aug 14, 2023

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