Let f(x)={ax+3, if x>2,x−5 if −2≤x≤2,2x−b if x<−2. Find a+b if the piecewise function is continuous (which means that its graph can be drawn without lifting your pencil from the paper).
Put 2 into each of the first two functions for x and set them equal
a(2) + 3 = 2 - 5
2a = 2 - 5 - 3
2a = -6
a = -3
Put - 2 into each of the last two functions for x and set them equal
-2 - 5 = 2(-2) - b
-7 = -4 - b
b = -4 + 7
b = 3
a + b = 3 + -3 = 0
Rigorously, continuity is defined below:
For every k in the domain of f;