+79 Let ABCD be a parallelogram. If AC = 9 and BD = 17, then find AB^2 + BC^2.
+118608
Let ABCD be a parallelogram. If AC = 9 and BD = 17, then find AB^2 + BC^2.
\(BC^2=4.5^2+8.5^2-(2*4.5*8.5*cos\alpha) \qquad (1)\\~\\ AB^2=4.5^2+8.5^2-(2*4.5*8.5*cos(180-\alpha))\\ AB^2=4.5^2+8.5^2+(2*4.5*8.5*cos(\alpha))\qquad (2)\\ (1)+(2)=\)
You can check and finish it
+118608 Do you repost because you are too lazy to finish it yourself?
https://web2.0calc.com/questions/still-stuck
To ignore an answer and then repost is the height of rudeness.
