If f(x)=x^3+3x^2+3x+1, find f^{-1}(2).
There is a way to find the exact value! :D
x^3 + 3x^2 + 3x + 1 = 2
(x+1)^3 = 2
x = 3√2−1
x3+3x2+3x+1=2x3+3x2+3x−1=0x≈0.26
Thanks Voldemort