Let x,y and z be positive real numbers such that x+y+z=1. Find the maximum value of x3y2z.
say x=1 and y and z=0 so 1*0*0=0 so answer is 0!
that was wrong
please double-check your answer (i can't risk getting this problem wrong )
????????
( i am on peralgebra not intimated algrebra!)
You get the maximum when x = y = z = 1/3. The maximum value is then (1/3)^6 = 1/729.
that was wrong as well but it's ok it is really hard problem
well it could be [biggest number],-[biggest number],1
so it is [biggest number]^5
+680 
+680 
)
