Hi Heurka,
I don't get what you did all that for?
Why is it reasonable to set
1x=ex×ln(1)
I mean I know that
1x=1
that is where i started but I do not understand why you put those lines of working in front of it.
1^ any real number = 1
So 1^x=1
The integral of 1 is x+c
I think that is the answer
integration of 1^x
∫1x dx ?
set1x=ex×ln(1)ln(1)=0so1x=ex×0x×0=0so1x=e0e0=1so1x=1∫1x dx=∫1 dx=x+c
Hi Melody,
it is not reasonable to set 1x=ex×ln(1),
but in general it is easier to integrate ex