Inequality

$\frac{\left(-2x-12\right)}{2}>7\left(3-4x\right)$

$\mathrm{Multiply\:both\:sides\:by\:}2$

$\frac{-2x-12}{2}\cdot \:2>7\left(3-4x\right)\cdot \:2$

$-2x-12>14\left(3-4x\right)$

$-2x-12>42-56x$

$\mathrm{Add\:}12\mathrm{\:to\:both\:sides}$

$-2x-12+12>42-56x+12$

$Simplify$

$-2x>-56x+54$

$\mathrm{Add\:}56x\mathrm{\:to\:both\:sides}$

$-2x+56x>-56x+54+56x$

$Simplify$

$54x>54$

$\mathrm{Divide\:both\:sides\:by\:}54$

$\frac{54x}{54}>\frac{54}{54}$

$Simplify$

$x>1$

-Vinculum