Inequality

Expanding: $2x^2+16x+30<3x^2+19x+6$

Combine like terms: $x^2+3x-24>0$

Quadratic formula: $x={-3\pm\sqrt{105}\over2}$, which are the two roots r and s, used in the factoring of the quadratic (x - r)(x - s) = x^2 + 3x - 24.

To be positive, we take the extreme values in which both (x - r) and (x - s) are positive or both negative, so our solution interval is:

$(-\inf, {-3-\sqrt{105}\over2})$ U $({-3 + \sqrt{105}\over2}, \inf)$