In the equation x^2+mx+n=0,m and n are intergers.The only possible for x is -3.What is the value of m?

Hello fiora!

In the equation x^2+mx+n=0,m and n are intergers.

The only possible for x is -3.What is the value of m?

A.3

B.-3

C.6

D.-6

E.9

$x^2+mx+n=0$

$x = -3$

$\left(x+ 3\right) ^{2}= x^{2} + 6x+ 9= 0$

$m = 6$ 

$Solution\ C\ is\ correct.$ 

Greeting asinus :- )  !

Thank you,asinus!Nice explanation and graphics representations.