In right triangle PQR, we have angle Q = angle R and PR = 6sqrt(2). What is the area of triangle PQR?
The area of triangle PQR is 1/2*6^2 = 18.
QR/2 = cos(45°) * 6sqrt(2) = 6
Height of triangle h = sin(45°) * 6sqrt(2) = 6
The area of triangle PQR = 6² = 36 u²
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