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Find the complex number z that satisfies

(1+i)z2¯z=11+25i.

 May 18, 2021
 #1
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z = 5 - 2i.

 May 19, 2021
 #2
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Find the complex number z that satisfies
(1+i)z2¯z=11+25i.

 

Set z=a+biSet ¯z=abi

 

(1+i)z2¯z=11+25i(1+i)(a+bi)2(abi)=11+25i(1+i)a+(1+i)bi2a+2bi=11+25ia+ia+bi+bi22a+2bi=11+25i|i2=1a+ia+bib2a+2bi=11+25i(a+b)+i(a+3b)=11+25icompare(a+b)=11a+b=11a=11b(a+3b)=2511b+3b=252b=14b=7a=11ba=117a=4z=a+biz=4+7i

 

laugh

 May 19, 2021

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