if i have 25547 and add 1410 to that sum i get = 26957. if i reduce that new sum with 5 % i get = 25609,15. if i repeat this process each day, how many days will it take to get to 27924?
You can get 28200 if u dont reduce it with 5 % the last day.
You get max 20 * 1410 = 28200.
tn=0.95n⋅(255470.95−20⋅1410)+20⋅1410 We have tn=27924 and get n by rearrange: n=ln(tn−20⋅1410255470.95−20⋅1410)ln(0.95)n=ln(27924−20⋅1410255470.95−20⋅1410)ln(0.95)n=ln(−276−1308.42105263)ln(0.95)n=ln(0.21094127112)ln(0.95)n=−1.55617552018−0.05129329439n=30.3387711544
It will take to get 27924 about 30.3387711544 days
day 30 = 27919.16
day 31 = 27933.20
$$\small{\text{$
\begin{array}{lr}
\small{\text{day }} 1 & 26957.00 \\
\small{\text{day }} 2 & 27019.15 \\
\small{\text{day }} 3 & 27078.19 \\
\small{\text{day }} 4 & 27134.28 \\
\small{\text{day }} 5 & 27187.57 \\
\small{\text{day }} 6 & 27238.19 \\
\small{\text{day }} 7 & 27286.28 \\
\small{\text{day }} 8 & 27331.97 \\
\small{\text{day }} 9 & 27375.37 \\
\small{\text{day }} 10 & 27416.60 \\
\small{\text{day }} 11 & 27455.77 \\
\small{\text{day }} 12 & 27492.98 \\
\small{\text{day }} 13 & 27528.33 \\
\small{\text{day }} 14 & 27561.92 \\
\small{\text{day }} 15 & 27593.82 \\
\small{\text{day }} 16 & 27624.13 \\
\small{\text{day }} 17 & 27652.92 \\
\small{\text{day }} 18 & 27680.28 \\
\small{\text{day }} 19 & 27706.26 \\
\small{\text{day }} 20 & 27730.95 \\
\small{\text{day }} 21 & 27754.40 \\
\small{\text{day }} 22 & 27776.68 \\
\small{\text{day }} 23 & 27797.85 \\
\small{\text{day }} 24 & 27817.96 \\
\small{\text{day }} 25 & 27837.06 \\
\small{\text{day }} 26 & 27855.20 \\
\small{\text{day }} 27 & 27872.44 \\
\small{\text{day }} 28 & 27888.82 \\
\small{\text{day }} 29 & 27904.38 \\
\small{\text{day }} 30 & 27919.16 \\
\small{\text{day }} 31 & 27933.20
\end{array}
$}}$$

if i have 25547 and add 1410 to that sum i get = 26957. if i reduce that new sum with 5 % i get = 25609,15. if i repeat this process each day, how many days will it take to get to 27924?
If I have properly understood: You get max 19 * 1410 = 26790
(19 = 0.95/0.05)
You never reach 27924!
I should have clarifyed.
You can get 28200 if u dont reduce it with 5 % the last day.
So how many days will it take to reach 27924 if u start at 25547, add 1410 each day and reduse that new totalsum with 5%?
On the day u reach 27924 u dont reduce the sum.
You can get 28200 if u dont reduce it with 5 % the last day.
You get max 20 * 1410 = 28200.
tn=0.95n⋅(255470.95−20⋅1410)+20⋅1410 We have tn=27924 and get n by rearrange: n=ln(tn−20⋅1410255470.95−20⋅1410)ln(0.95)n=ln(27924−20⋅1410255470.95−20⋅1410)ln(0.95)n=ln(−276−1308.42105263)ln(0.95)n=ln(0.21094127112)ln(0.95)n=−1.55617552018−0.05129329439n=30.3387711544
It will take to get 27924 about 30.3387711544 days
day 30 = 27919.16
day 31 = 27933.20
$$\small{\text{$
\begin{array}{lr}
\small{\text{day }} 1 & 26957.00 \\
\small{\text{day }} 2 & 27019.15 \\
\small{\text{day }} 3 & 27078.19 \\
\small{\text{day }} 4 & 27134.28 \\
\small{\text{day }} 5 & 27187.57 \\
\small{\text{day }} 6 & 27238.19 \\
\small{\text{day }} 7 & 27286.28 \\
\small{\text{day }} 8 & 27331.97 \\
\small{\text{day }} 9 & 27375.37 \\
\small{\text{day }} 10 & 27416.60 \\
\small{\text{day }} 11 & 27455.77 \\
\small{\text{day }} 12 & 27492.98 \\
\small{\text{day }} 13 & 27528.33 \\
\small{\text{day }} 14 & 27561.92 \\
\small{\text{day }} 15 & 27593.82 \\
\small{\text{day }} 16 & 27624.13 \\
\small{\text{day }} 17 & 27652.92 \\
\small{\text{day }} 18 & 27680.28 \\
\small{\text{day }} 19 & 27706.26 \\
\small{\text{day }} 20 & 27730.95 \\
\small{\text{day }} 21 & 27754.40 \\
\small{\text{day }} 22 & 27776.68 \\
\small{\text{day }} 23 & 27797.85 \\
\small{\text{day }} 24 & 27817.96 \\
\small{\text{day }} 25 & 27837.06 \\
\small{\text{day }} 26 & 27855.20 \\
\small{\text{day }} 27 & 27872.44 \\
\small{\text{day }} 28 & 27888.82 \\
\small{\text{day }} 29 & 27904.38 \\
\small{\text{day }} 30 & 27919.16 \\
\small{\text{day }} 31 & 27933.20
\end{array}
$}}$$
