x-y=1
y-2z=1
3x-4z=7
x=?
y=?
z=?
(1)x−y=1x=1+y(2)y−2z=1y=1+2z(3)3x−4z=73x=7+4zx=1+y3(1+y)=7+4zy=1+2z3[1+(1+2z)]=7+4z3(1+1+2z)=7+4z3(2+2z)=7+4z6+6z=7+4z|−4z6+6z−4z=76+2z=7|−62z=7−62z=1|:2z=0.5(2)y=1+2zy=1+2(0.5)y=1+1y=2(1)x=1+yx=1+2x=3