I really need help with this question, I do not understand matrices.
Let u and v be vectors such that ∥u∥=3 and ∥v∥=2 such that the angle between u and v when placed tail to tail is 60∘.
Let A be a matrix such that
row1(A)=u,row2(A)=v.
Then what is Au,Av in that order?
Thanks in advance!
Hi Guest!
Ok, this question is about matrix multiplicaton and the dot product (Also called: Inner product or scalar product).
u is a vector, so it has components: u1,u2,...un
Similarly, v is a vector, so it has components: v1,v2,...,vn
Now, no need to actually make it in n-dimension. I mean we can, but why not simplify this and assume we are in 2 dimensional space?
That is, n=2
So, u = and v =
So our matrix A is: A=[u1u2v1v2] (As given, u is the first row and v is the second row)
But we are given an angle and lengths of these vectors. Can we find the "dot product"?
Yes: u˙v=u1v1+u2v2=cos(θ)∗||u||∗||v||=cos(60)∗3∗2=3
So, we got: u1v1+u2v2=3
Next, let's see what the question really wants:
Au=[u1u2v1v2] ∗[u1u2] = (u21+u22u1v1+u2v2) = (323)=(93)
Now, in a similar way, find Av.
Hope this helps!
The dot product of u and v is equal to ||u||* ||v||*cos 60 = 3. (Prove this before you start using it!)
row_1(Au) = u⋅u = 9
row_2(Au) = Dot product of u and v, equaling 3
Au = <9, 3>
Similarly:
row_1(Av) = 3
row_2(Av) = v \cdot v = 4
Av = <3, 4>
There seems to be a notational or transcription error in the question.
The statement that the first row of the matrix A is the vector u implies that u is a row vector.
(Similarly, the implication is that v is a row vector.)
We are not given the dimension of u and v, but assuming that it is two, A will be a 2 by 2 matrix.
In that case, the products Au and Av do not exist, for the products to exist u and v would need to be column vectors.
The question would make sense if we were given that
row1(A)=uT,
(and similarly for v),
or, calculate
AuT,
(If u is a row vector.)