+0  
 
0
1047
2
avatar+283 

If two numbers will be randomly chosen without replacement from {3,4,5,6} , what is the probability that their product will be a multiple of 9? Express your answer as a common fraction.

 Nov 15, 2018
 #1
avatar+6244 
+2

\(\text{There are a total of }\dbinom{4}{2}=6 \text{ pairs} \\ (3,6) \text{ is the only pair whose product is a multiple of }9\\ \text{So }p=\dfrac 1 6\)

.
 Nov 15, 2018
 #2
avatar+283 
0

Thank you, I appreciate it.

 Nov 15, 2018

3 Online Users

avatar
avatar