I need help

First, let's combine all our like terms and move all the terms to oneside. We get

$6x^{2}-21x-31=0$

Now, we use the quadratic equation. We get that

$x=\frac{-({-21})\pm \sqrt{{-21})^{2}-4\cdot {6}({-31})}}{2\cdot {6}}$

Simplifying furher. We get 2 values for x We get

$x=\frac{\sqrt{1185}+21}{12}\\ x=\frac{-\sqrt{1185}+21}{12}$

Clearly, the first value of x is greater in this case, so we have

$x=\frac{\sqrt{1185}+21}{12}$ as our final anwer. 

Thanks! :)