i need help solving this linear equation please. Can you also include the steps of the solution. Thanks.

i need help soving this linear equation please. Can ypu also include the steps of the solution. Thanks.

159b + 3.3c = 1000mg

2.3b + 0.6c = 18mg

$\small{ \begin{array}{lrcl} (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \\ \\ \hline \\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \qquad | \qquad -2.3\cdot b\\ & 0.6\cdot c &=& 18 - 2.3\cdot b \qquad | \qquad : 0.6\\ & c &=& \frac{ 18 - 2.3\cdot b } { 0.6 } \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot b \\ \\ \hline \\ c \text{ into } (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ & 159\cdot b + 3.3\cdot ( 30 - \frac{ 2.3 } { 0.6 }\cdot b ) &=& 1000 \\ & 159\cdot b + 3.3\cdot 30 - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b &=& 1000 \\ & 159\cdot b - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b + 3.3\cdot 30 &=& 1000\qquad | \qquad - 3.3\cdot 30\\ & 159\cdot b - 3.3 \cdot \frac{ 2.3 } { 0.6 }\cdot b &=& 1000 - 3.3\cdot 30\\ & 159\cdot b - 12.65\cdot b &=& 1000 - 99\\ & 159\cdot b - 12.65\cdot b &=& 901\\ & b\cdot (159 - 12.65) &=& 901\\ & b\cdot 146.35 &=& 901\\ & b &=& \frac{901} {146.35}\\ & \mathbf{b} & {=} & \mathbf{6.15647420567} \\ \\ \hline \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot b \\ & c &=& 30 - \frac{ 2.3 } { 0.6 }\cdot\frac{901} {146.35} \\ & c &=& 30 - 23.5998177884 \\ & \mathbf{c} & {=} & \mathbf{6.40018221159} \\ \\ \hline \\ (1) & 159\cdot b + 3.3\cdot c &=& 1000 \\ & 159\cdot 6.15647420567 + 3.3 \cdot 6.40018221159 &=& 1000 \qquad \text{okay!} \\\\ (2) & 2.3\cdot b + 0.6\cdot c &=& 18 \\ & 2.3 \cdot 6.15647420567 + 0.6 \cdot 6.40018221159 &=& 18 \qquad \text{okay!} \end{array} }$

Thank you so much!