During a class trip trip to a farm, you determined that there were 116 legs in the farmyard. The only two animals there were chickens and cows. if there were 46 animals, how many were chickens ( chickens have two legs, cows have four )
During a class trip trip to a farm, you determined that there were 116 legs in the farmyard. The only two animals there were chickens and cows. if there were 46 animals, how many were chickens ( chickens have two legs, cows have four )
cows = x and chickens = y
4 legs * x + 2*legs * y = 116 legs | :2
(2) ´2x + y = 58
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(1) x + y = 46
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(2)-(1): 2x - x + y - y = 58-46
x + 0 = 12
x = 12
There are 12 cows
(1) x + y = 46
12 + y = 46 | -12
y = 46 - 12 = 34
There are 34 chickens
let the number of chickens be H (hens, okay?)
so the number of cows must be 46 - H
∴total number of legs = H*2 + ..........
can you finish this now?
During a class trip trip to a farm, you determined that there were 116 legs in the farmyard. The only two animals there were chickens and cows. if there were 46 animals, how many were chickens ( chickens have two legs, cows have four )
cows = x and chickens = y
4 legs * x + 2*legs * y = 116 legs | :2
(2) ´2x + y = 58
--------------------------------------------------------
(1) x + y = 46
--------------------------------------------------------
(2)-(1): 2x - x + y - y = 58-46
x + 0 = 12
x = 12
There are 12 cows
(1) x + y = 46
12 + y = 46 | -12
y = 46 - 12 = 34
There are 34 chickens