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The questions is "A polynomial P(x) and a divisor d(x) are given. Use long division to find the quotient Q(x) and the remainder R(x). Express in the form P(x)=d(x)*q(x)+R(x)

P(x)=x^3 -27

d(x)=x+3

x^3 -27=(x+3)( _ ) - __

 Oct 6, 2015

Best Answer 

 #2
avatar+26397 
+30

The questions is "A polynomial P(x) and a divisor d(x) are given. Use long division to find the quotient Q(x) and the remainder R(x). Express in the form P(x)=d(x)*q(x)+R(x)

P(x)=x^3 -27

d(x)=x+3

 

(x327):(x+3)=x23x+954x+3|(x+3)(x327)=(x+3)(x23x+9)54

 

laugh

 Oct 6, 2015
 #1
avatar+118703 
+10

It is difficult to lay this out properly on the forum but it is quite literally done the same as a number long division.

 

I'll see if I can find another example :/

 

Here is one example :/

http://web2.0calc.com/questions/3x-3-5x-2-10x-3-3x-4

 

 

If you google "Algebraic long division"  There are a heap of sites and more than one good you tube clip that deals with this topic.  

 Oct 6, 2015
 #2
avatar+26397 
+30
Best Answer

The questions is "A polynomial P(x) and a divisor d(x) are given. Use long division to find the quotient Q(x) and the remainder R(x). Express in the form P(x)=d(x)*q(x)+R(x)

P(x)=x^3 -27

d(x)=x+3

 

(x327):(x+3)=x23x+954x+3|(x+3)(x327)=(x+3)(x23x+9)54

 

laugh

heureka Oct 6, 2015
 #3
avatar+130477 
+5

               x^2   - 3x    + 9

 

x + 3   [   x^3  - 0x^2   - 0x   - 27 ]

              x^3  + 3x^2

           ---------------------------------

                       -3x^2  - 0x

                      -3x^2  -  9x

                     ------------------

                                    9x   -  27

                                    9x  +  27

                                  --------------

                                          - 54

 

So...we have     [ x ^3 - 27 ] =  [x + 3] *   [ x^2 - 3x + 9]   - 54

 

 

cool cool cool

 Oct 6, 2015

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