How would i find x in the equation: 14^x=91

14^x=91

$$\small{\text{ $ \begin{array}{rcl} 14^x &=& 91 \quad | \quad \ln() \\ \ln(14^x) &=& \ln(91) \\ x\cdot \ln(14) &=& \ln(91) \\\\ x &=& \dfrac{\ln(91)} { \ln(14)} \\\\ x &=& \dfrac{4.51085950652} { 0.32220425047} \\\\ x &=& 1.70926923637 \end{array} $ }}$$

$$14^{1.70926923637} = 91$$

or

$$\small{\text{ $ \begin{array}{rcl} 14\cdot x &=& 91 \\\\ x = \dfrac{91}{14} \\\\ x = 6.5 \end{array} $ }}$$

$$14\cdot 6.5= 91$$

My teacher taught us to guess and check.. 14*14=?*14=? until you get 91.