+26367 How to get from this:
sk1/3 = δk.
to this
k2/3 = s/δ
k = (s/δ)3/2.
\(\begin{array}{|rcll|} \hline \delta k \quad &=& sk^{\frac{1}{3}} \quad & | \quad : \delta \\\\ k &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad k = k^1 \\\\ k^1 &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad k^1=k^{\frac{3}{3}} \\\\ k^{\frac{3}{3}} &=& \dfrac{s}{\delta} k^{\frac{1}{3}} \quad & | \quad : k^{\frac{1}{3}} \\\\ \dfrac{ k^{\frac{3}{3}} } { k^{\frac{1}{3}} } &=& \dfrac{s}{\delta} \\\\ k^{\frac{3}{3}} k^{-\frac{1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{3}{3}-\frac{1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{3-1}{3}} &=& \dfrac{s}{\delta} \\\\ k^{\frac{2}{3}} &=& \dfrac{s}{\delta} \\\\ \left(k^{\frac{2}{3}}\right)^{\frac{3}{2}} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k^{\frac{2}{3}\cdot \frac{3}{2}} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k^{1} &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\\\ k &=& \left(\dfrac{s}{\delta} \right)^{\frac{3}{2}} \\ \hline \end{array}\)
