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x+1/x=4; x^3+1/x^3=?

 

after making a quadratic equation of this, which btw doesn't factorize, I am stuck in the square root of 12. Also, is there any other way to find the value of x or the answer?

 Mar 8, 2016

Best Answer 

 #1
avatar+26396 
+10

x+1/x=4;

x^3+1/x^3=?

 

x+1x=4|()3(x+1x)3=43x3+3x21x+3x1x2+1x3=64x3+3x+3x+1x3=64x3+1x3+3x+3x=64x3+1x3+3(x+1x)=64|x+1x=4x3+1x3+34=64x3+1x3+12=64|12x3+1x3=6412x3+1x3=52

 

laugh

 Mar 8, 2016
 #1
avatar+26396 
+10
Best Answer

x+1/x=4;

x^3+1/x^3=?

 

x+1x=4|()3(x+1x)3=43x3+3x21x+3x1x2+1x3=64x3+3x+3x+1x3=64x3+1x3+3x+3x=64x3+1x3+3(x+1x)=64|x+1x=4x3+1x3+34=64x3+1x3+12=64|12x3+1x3=6412x3+1x3=52

 

laugh

heureka Mar 8, 2016

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