+130478 how many numbers between 1 and 100 (inclusive) are divisible by 3 and 5.
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Since 3 and 5 are relatively prime (they have no common divisors except 1) this should be easy to determine.
The first multiple of 3 and 5 is 15 = 3*5*1 = 15*(1)
The second one is 30 = 3*5*2 = 15*(2)
Then by solving this inequality....... 15(n) ≤ 100....you should be able to determine how many numbers between 1 and 100 (inclusive) are divisible by 3 and 5. If you get a "remainder," just ignore it - "n" is an integer.
+130478 how many numbers between 1 and 100 (inclusive) are divisible by 3 and 5.
-----------------------------------------------------------------------------------------------------------------------------
Since 3 and 5 are relatively prime (they have no common divisors except 1) this should be easy to determine.
The first multiple of 3 and 5 is 15 = 3*5*1 = 15*(1)
The second one is 30 = 3*5*2 = 15*(2)
Then by solving this inequality....... 15(n) ≤ 100....you should be able to determine how many numbers between 1 and 100 (inclusive) are divisible by 3 and 5. If you get a "remainder," just ignore it - "n" is an integer.
