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How many different combinations of quarters, nickels, and dimes can be used to make $0.55?

 Apr 21, 2015

Best Answer 

 #3
avatar+26396 
+5

Quater =25Dime =10 Nickel =5In $0.55 max. 2 Quaters, max. 5 Dimes and max. 11 Nickels (2i=0x(25i))×(5i=0x(10i))×(11i=0x(5i))=(1+x25+x50)×(1+x10+x20+x30+x40+x50)×(1+x5+x10+x15+x20+x25+x30+x35+x40+x45+x50+x55)=(x155)+(x150)+2x145+2x140+3x135+4x130+5x125+6x120+7x115+8x110+10x105+11x100+11x95+12x90+12x85+13x80+13x75+12x70+12x65+11x60+11x55+10x50+8x45+7x40+6x35+5x30+4x25+3x20+2x15+2x10+(x5)+1

 

The coefficient from  x55 is 11. So there are 11 possibilities.

 Apr 21, 2015
 #1
avatar+130474 
+5

Let's see.......

2 quarters  1 nickel

1 quarter  3 dimes

1 quarter 2 dimes  2 nickels

1 quarter  1 dime 4 nickels

1 quarter 6 nickels

5 dimes 1 nickel

4 dimes 3 nickels

3 dimes 5 nickels

2 dimes 7 nickels

1 dime 9 nickels

11 nickels

 

I think that's it......did I leave anything  out ???

 

  

 Apr 21, 2015
 #2
avatar+26396 
+5

 

How many different combinations of quarters, nickels, and dimes can be used to make $0.55 ?

 

  1.$0.55=3Dimes+1Quater2.$0.55=1Nickel+2Quaters3.$0.55=1Nickel+5Dimes4.$0.55=2Nickels+2Dimes+1Quater5.$0.55=3Nickels+4Dimes6.$0.55=4Nickels+1Dime+1Quater7.$0.55=5Nickels+3Dimes8.$0.55=6Nickels+1Quater9.$0.55=7Nickels+2Dimes10.$0.55=9Nickels+1Dime11.$0.55=11Nickels

 Apr 21, 2015
 #3
avatar+26396 
+5
Best Answer

Quater =25Dime =10 Nickel =5In $0.55 max. 2 Quaters, max. 5 Dimes and max. 11 Nickels (2i=0x(25i))×(5i=0x(10i))×(11i=0x(5i))=(1+x25+x50)×(1+x10+x20+x30+x40+x50)×(1+x5+x10+x15+x20+x25+x30+x35+x40+x45+x50+x55)=(x155)+(x150)+2x145+2x140+3x135+4x130+5x125+6x120+7x115+8x110+10x105+11x100+11x95+12x90+12x85+13x80+13x75+12x70+12x65+11x60+11x55+10x50+8x45+7x40+6x35+5x30+4x25+3x20+2x15+2x10+(x5)+1

 

The coefficient from  x55 is 11. So there are 11 possibilities.

heureka Apr 21, 2015

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