how do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

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Guest Feb 9, 2015

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The geometric mean of of any set of N numbers is just the nth root of their product =

ⁿ√(a*b*c*d*...*n)

CPhill Feb 10, 2015

CPhill · Answer 1 · 2015-02-10T02:03:42

The geometric mean of of any set of N numbers is just the nth root of their product =

ⁿ√(a*b*c*d*...*n)

Fireshot360 · Answer 2 · 2015-02-09T06:49:29

Do you mean like "3,5,6,7,9,1 = (Mean) 5.6666666661 = 6?

Melody · Answer 3 · 2015-02-10T05:15:38

I think that it is 3,x,9

$x/3=9/x x^2=27 x= \sqrt{27}=3\sqrt3$

heureka · Answer 4 · 2015-02-10T01:57:02

How do you find the geometric mean of a pair of numbers and put it in the simplest radical form? (e.g. 3 and 9)

For instance, the geometric mean of two numbers, say 2 and 8,

is just the square root of their product; that is

$\sqrt{2\cdot 8}=4$ .

$\small{\text{ The geomeric mean of the pair of numbers 3 and 9 is: $ \sqrt[2]{3*9}= \sqrt[2]{3}* \sqrt[2]{9}= \sqrt[2]{3}* 3 $ }}$