Compute tan300 and tan60
tan300=-sqrt3 and tan60=sqrt3 so we have tan300=−√3 and tan60=√3
is this correct
This is correct thanks jimkey17
Remember tan = sin / cos so for 60o tan 60 = sqrt3/2 / 1/2 = sqrt 3
tan 300 = -sqr3/2 / 1/2 = - sqrt 3
+37165 
