Hi good people!,

Question

Hi good people!,

0

994

8

+1124

Hi good people!,

How do I go about finding the general term for the following sequence:

${1\over3};{8\over9};1;{64\over81}$

I have tested the sequence for Arithmetic, Geometric and Quadratic...but cannot determine which...please help...

juriemagic Jul 25, 2018

8⁺⁰ Answers

1 Online Users

Alan · Answer 1 · 2018-07-25T08:34:39

Try the following:

$1^3\frac{1}{3}; 2^3\frac{1}{3}^2;3^3\frac{1}{3}^3;4^3\frac{1}{3}^4;...etc$

heureka · Answer 2 · 2018-07-25T08:41:45

#2

+26400

+1

Hi good people!,
How do I go about finding the general term for the following sequence:
{1\over3};{8\over9};1;{64\over81}

$\displaystyle {1\over3};{8\over9};1;{64\over81}$

$\huge{ \begin{array}{|rcll|} \hline a_1 &=& {1\over3} \\\\ a_2 &=& {8\over9} \\\\ a_3 &=& 1 \\\\ a_4 &=& {64\over81} \\\\ \ldots \\\\ a_n &=& \dfrac{n^3}{3^n} \\ \hline \end{array} }$

heureka Jul 25, 2018

#3

0

Hi Heureka,

I have no idea why the answer is what you say it is...How you get to it....thanx anyways...

Guest Jul 25, 2018

#3

0

Hi Heureka,

I have no idea why the answer is what you say it is...How you get to it....thanx anyways...

Guest Jul 25, 2018

#7

+26400

+1

I have no idea why the answer is what you say it is...How you get to it....thanx anyways...

$\huge{ \begin{array}{|lrlrlrlrlrl|} \hline & a_{\color{red}1} &;& a_{\color{red}2}&;& a_{\color{red}3} &;& a_{\color{red}4} &;& \ldots &;& a_{\color{red}n} \\ \hline & \dfrac{1}{3}&;& \dfrac{8}{9}&;& 1&;& \dfrac{64}{81}&;& \ldots &;& \\\\ \Rightarrow & \dfrac{1^1}{3^1}&;& \dfrac{2^3}{3^2}&;& 1&;& \dfrac{4^3}{3^4}&;& \ldots &;& \\\\ \Rightarrow & \dfrac{{\color{red}1}^1}{3^{\color{red}1}}&;& \dfrac{{\color{red}2}^3}{3^{\color{red}2}}&; & \dfrac{{\color{red}3}^3}{3^{\color{red}3}}&;& \dfrac{{\color{red}4}^3}{3^{\color{red}4}}&;& \ldots &;&\dfrac{{\color{red}n}^3}{3^{\color{red}n}} \\ \hline \end{array} }$

heureka Jul 25, 2018

edited by heureka Jul 25, 2018

#8

+1124

+2

Heureka,

thank you kindly...makes sooo much sense!!!..

juriemagic Jul 25, 2018

Hi good people!,

0 users composing answers..

8⁺⁰ Answers

1 Online Users

Top Users

Sticky Topics

Hi good people!,

0 users composing answers..

8+0 Answers

1 Online Users

Top Users

Sticky Topics

8⁺⁰ Answers