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f(2x)=[f(x)]^2

Given the equation above, if f(1)=3, what is f(2) ?

Solveit Dec 10, 2015

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Solveit Dec 10, 2015

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Best Answer

f(2x)=[f(x)]^2

Given the equation above, if f(1)=3, what is f(2) ?

$f(2x)=[f(x)]^2\\~\\ f(1)=3\\~\\ f(2*1)=[f(1)]^2\\~\\ f(2)=[f(1)]^2\\~\\ f(2)=[3]^2\\~\\ f(2)=9$

Melody Dec 11, 2015

Melody · Answer 1 · 2015-12-11T11:38:35

f(2x)=[f(x)]^2

Given the equation above, if f(1)=3, what is f(2) ?

$f(2x)=[f(x)]^2\\~\\ f(1)=3\\~\\ f(2*1)=[f(1)]^2\\~\\ f(2)=[f(1)]^2\\~\\ f(2)=[3]^2\\~\\ f(2)=9$

Hayley1 · Answer 2 · 2015-12-10T04:59:07

This is kind of trickyy. :/

Hayley1 · Answer 3 · 2015-12-10T05:20:00

Do you have any other questions? I'll try my best!

Solveit · Answer 4 · 2015-12-10T05:24:46

i am doing tests right now if i have any question i will contact with you :)