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The fourth degree polynomial equation x47x3+4x2+7x4=0 has four real roots, a, b, c, and d. What is the value of the sum 1a+1b+1c+1d? Express your answer as a common fraction.

 Jun 4, 2019

Best Answer 

 #1
avatar+6252 
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abcd=c0=4bcd+acd+abd+abc=(c1)=71a+1b+1c+1d=bcd+acd+abd+abcabcd=74=74

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 Jun 4, 2019
 #1
avatar+6252 
+1
Best Answer

abcd=c0=4bcd+acd+abd+abc=(c1)=71a+1b+1c+1d=bcd+acd+abd+abcabcd=74=74

Rom Jun 4, 2019

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