help !!!!!

Remember how to find the slope between two points  ?    ( y1-y2) /(x1-x2) = m = slope = 1/3

y = mx + b

y = 1/3 x + b     sub in one of the points to calculate 'b'

-2 = 1/3 (6) + b       then b = -4

y = 1/3 x -4

The slope intercept form is: $y=mx+b$

First you need to find the slope (m). $m=\frac{y_2−y_1}{x_2-x_1}.$

$m=\frac{−2−\left(−5\right)}{6−\left(−3\right)}$

$m=\frac13$

Next, you find the y-intercept, or b. You can plug in any of the 2 points like this: $y=\frac13x+b$

$-2=\frac13\cdot6+b$

$2+b=-2$

$b=-4$

So our final answer is $y=\frac13x-4$

(I just wanted to make ElectricPavlov's solution more clear)