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A worker is paid 0.05 on the first day, 0.10 on the second day, 0.20 on the third day and 0.40 on the fourth day, and so on. How much money in total does the work earn after working 21 days?

 Mar 4, 2016
 #1
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A worker is paid 0.05 on the first day, 0.10 on the second day, 0.20 on the third day and 0.40 on the fourth day, and so on. How much money in total does the work earn after working 21 days?

 

after 1 day :0.05after 2 days :0.10=0.052after 3 days :0.20=0.102=0.0522=0.0522after 4 days :0.40=0.202=0.052222=0.0523after 21 days :0.052211=0.05220=0.051048576=52428.80

 

He earn after 21 days 52428.80

 

laugh

 Mar 4, 2016
edited by heureka  Mar 4, 2016
 #3
avatar+26398 
0

A worker is paid 0.05 on the first day, 0.10 on the second day, 0.20 on the third day and 0.40 on the fourth day, and so on. How much money in total does the work earn after working 21 days?

 

after 1 day :0.05after 2 days :0.10=0.052after 3 days :0.20=0.102=0.0522=0.0522after 4 days :0.40=0.202=0.052222=0.0523after 21 days :0.052211=0.05220=0.051048576=52428.80

 

 

all days together:

geometric sequence

a1=0.05

r=2

 

s=a1(1r211r)s=a1(r211r1)s=0.05(221121)s=0.05(22111)s=0.05221s=0.052097152s=104857.60

 

laugh

heureka  Mar 4, 2016
 #4
avatar+26398 
0

A worker is paid 0.05 on the first day, 0.10 on the second day, 0.20 on the third day and 0.40 on the fourth day, and so on. How much money in total does the work earn after working 21 days?

 

without mistake:

 

all days together:

geometric sequence

a1=0.05

r=2

 

s=a1(1r211r)s=a1(r211r1)s=0.05(221121)s=0.05(22111)s=0.05(2211)s=0.052097151s=104857.55

 

laugh

heureka  Mar 4, 2016
 #2
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For the 21st.day only, he earns: .05 X 2^(21-1)=.05 X 2^20=52,428.8 cents=$524.29.

For the TOTAL of the 21 days  : .05 X 2^21     =.05 X 2^21=104,857.6cents=$1,048.58

 Mar 4, 2016

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