The product of all the prime numbers between 1 and 100 is equal to P. What is the remainder when P is divided by 16?
+447 Skip the first prime 22 and look for the product modulo 88. The twenty-four odd primes <100<100 are
3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97.3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97.
Modulo 88, these are
3,5,7,3,5,1,3,7,5,7,5,1,3,7,5,3,5,3,7,1,7,3,1,13,5,7,3,5,1,3,7,5,7,5,1,3,7,5,3,5,3,7,1,7,3,1,1
so their product is
15375676≡3(mod8)15375676≡3(mod8)
(where we might profit from using x2≡1(mod8)x2≡1(mod8) for odd xx). Thus P≡6(mod16)P≡6(mod16).
Thus the Answer you are looking for
6
