Find constants A and B such that x+7x2−x−2=Ax−2+Bx+1 for all x such that x≠−1 and x≠2. Give your answer as the ordered pair (A,B).
\frac{x + 7}{x^2 - x - 2} = \frac{A}{x - 2} + \frac{B}{x + 1}
x+7x2−x−2=Ax−2+Bx+1A(x+1)+B(x−2)=x+7Ax+Bx=xA−2B=7A+B=1A=7+2b7+2B+B=17+3B=13B=−6B=−2A=3 check3(x+1)−2(x−2)=x+7great
answer (3,-2)
That is not a problem Alan
Maybe 2 answers are better than one and it certainly is not your fault if Lightning double posted.