+152 Let line \(l_1 \) be the graph of \(5x+8y=-9\). Line \(l_2 \) is perpendicular to line \(l_1 \) and passes through the point \((10,10)\). If line \(l_2\) is the graph of the equation \(y=mx+b\), then find \(m+b \).
+36915 l1 is re-written as y = -5/8 x -9/8 slope m is -5/8
l2 perpindicular slope is -1/(-5/8) = 8/5
y = 8/5 x + b sub in point 10,10
10 = 8/5 (10) + b
b = 10 - 80/5 = -30/5
-30/5 +8/5= -22/5
