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how do I do this 13^-14/13^-7 , this 8^9*8^5,and this 2^-1/2^7still end up with exponents

they are all separate problems please and thank you

 Nov 28, 2016
 #2
avatar+33616 
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Use the fact that  a^x/a^y = a^(x-y)  and a^x*a^y = a^(x+y)

 

So 13^-14/13^-7 = 13^(-14 - -7) → 13^(-14 + 7) → 13^-7

 

8^9*8^5 = 8^(9+5) → 8^14

 

I'll leave you to try your third one!

.

 Nov 28, 2016
 #3
avatar+790 
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thx alan

owlface13  Nov 28, 2016
 #4
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13^-14/13^-7 = 1 / (13^14 / 13^7) = 1 / 13^(14 - 7) =1 / 13^7 =1/62,748,517.

 

8^9*8^5 = 8^(9+5) =8^14 =4,398,046,511,104

 

2^-1/2^7 = I choose to take it as: 2^(-1) /2^7, if so, then we have:

1 / (2 x 2^7) =1/2^8 =1 / 256

 Nov 28, 2016

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