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A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?

 Feb 17, 2016
 #1
avatar+26397 
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A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?

 

parabola: y=ax2+bx+c

focus: (xf=2, yf=7)

vertex:  (xv=2, yv=2)

directrix: y=cb2+14a

 

 xf=b2ayf=cb214axv=b2ayv=cb24a 

 

1. a?

yf=cb214a=cb24a+14ayv=cb24ayfyv=14aa=14(yfyv)a=14(7(2))a=149a=136

 

2. b?

xv=b2ab2a=xvb=2axvb=2136(2)b=4136b=19

 

3. c?

yv=cb24ab24a+yv=cc=b24a+yvc=(19)24(136)+(2)c=192c=179

 

The equation of the parabola is y=136x2+19x179

 

4. directrix

y=cb2+14ay=179(19)2+14136y=1799(181+1)y=179199y=29y=11

 

The equation of the parabolas directrix is y = -11

 

laugh

 Feb 17, 2016
edited by heureka  Feb 17, 2016
 #2
avatar+118703 
0

A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?

 

Draw a skech and you can almost see the answer immediately.

The focus and vertex lie n the vertical line x=-2

The vertex is below the focus so it is concave up.

The focus and the directrix are 7--2=9 units apart.

so the directrix will be 9 units below the vertex.

-2-9=-11

The directrix is     y= -11

 Feb 17, 2016

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