A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?
A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?
parabola: y=ax2+bx+c
focus: (xf=−2, yf=7)
vertex: (xv=−2, yv=−2)
directrix: y=c−b2+14a
xf=−b2ayf=c−b2−14axv=−b2ayv=c−b24a
1. a?
yf=c−b2−14a=c−b24a+14ayv=c−b24ayf−yv=14aa=14⋅(yf−yv)a=14⋅(7−(−2))a=14⋅9a=136
2. b?
xv=−b2ab2a=−xvb=−2⋅a⋅xvb=−2⋅136⋅(−2)b=4⋅136b=19
3. c?
yv=c−b24ab24a+yv=cc=b24a+yvc=(19)24⋅(136)+(−2)c=19−2c=−179
The equation of the parabola is y=136x2+19x−179
4. directrix
y=c−b2+14ay=−179−(19)2+14⋅136y=−179−9⋅(181+1)y=−179−19−9y=−2−9y=−11
The equation of the parabolas directrix is y = -11
A parabola has its focus at (–2, 7) and its vertex at (–2, –2). What is the equation of the parabolas directrix?
Draw a skech and you can almost see the answer immediately.
The focus and vertex lie n the vertical line x=-2
The vertex is below the focus so it is concave up.
The focus and the directrix are 7--2=9 units apart.
so the directrix will be 9 units below the vertex.
-2-9=-11
The directrix is y= -11