Help!

slope of the line that passes through  (3, -3)  and  (-5, 2)   =   $\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{2--3}{-5-3}\,=\,-\frac{5}{8}$

The line  l₁  passes through the point  (3, -3)  and has a slope of  $-\frac58$   .

So the equation of  l₁ in point-slope form is...

y - -3  =  $-\frac58$(x - 3)       Now we just have to get this equation in the form Ax + By  =  C

y + 3  =  $-\frac58$(x - 3)

                                     Multiply both sides of the equation through by  8 .

8y + 24  =  -5(x - 3)

                                     Distribute the  -5  to the terms in parenthesees.

8y + 24  =  -5x + 15

                                     Subtract  24  from both sides of the equation.

8y  =  -5x + 15 - 24

8y  =  -5x - 9

                                     Add  5x  to both sides of the equation.

5x + 8y  =  -9

5 ,  8 , and  -9  are integers with the greatest common divisor  1 , and  5  is positive.

5 + 8 + -9   =   4