The area of a rectangle is 432 square centimeters. What would the new area be if the length of the rectangle was decreased by %10 and the width of the rectangle was increased by 10% ? Express your answer to the nearest whole number.
+128406 Old area = L * W
New area =
( 1.1L) (.90 W)
( 1.1 L) ( .90 W)
L * W * (1.1) (.9)
L * W * (.99)
So....the new area is just 99% of 432 cm^2 ≈ 428 cm^2
+220 To solve this problem, let's declare variables.
L = length
W = width
(.90L)*(1.1W) = .99 of the total area.
432*.99 equals 427.68 sq. cm.
So 428 sq. cm. is the updated(or changed) area.
~~Hypotenuisance
