+1245 Regions I, II and III are bounded by squares. The perimeter of region I is 12 units and the perimeter of region II is 24 units. What is the ratio of the area of region I to the area of region III? Express your answer as a common fraction.
+6251 The mathy way of doing this is noting that for a square the perimeter is a function of s while the area is a function of s2
So an increase in the perimeter by a factor of K leads to an increase in area by a factor of K2
or in even more mathy terms, the area is directly proportional to the square of the perimeter
Another way of putting this is
A1A2=(P1P2)2A1A2=(1224)2=14
