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Nth Term =F + [N - 1] x D, where F=First term, N=Nth term, D=Common Difference.

5th term of your progression =11 + [5 - 1] x 6 =35

11 17 23 29 find, in terms of n, an expression for the nth term of this arithmatic sequence

$\begin{array}{|rcll|} \hline a_1 = 11+0\cdot 6 &=& 11 \\ a_2 = 11+1\cdot 6 &=& 17 \\ a_3 = 11+2\cdot 6 &=& 23 \\ a_4 = 11+3\cdot 6 &=& 29 \\ \dots \\ a_n = 11+(n-1)\cdot 6 &=& 5+6n \\ \hline \end{array}$