help with probabilities as fractions

any probability is between 0 and 1 so 62 is a non-starter

there are 32 total marbles in the bag

a) $P[\text{drawing a green marble}] = \dfrac{6}{32}=\dfrac{3}{16}$

b) $P[\text{drawing a red marble}] = \dfrac{10}{32}=\dfrac{5}{16}$

c) The easiest way to do this is find the probability of drawing a yellow marble and subtracting that from 1

$P[\text{drawing a !yellow marble}] = 1-P[\text{drawing a yellow marble}] = 1 - \dfrac{12}{32} = \dfrac{20}{32} = \dfrac{5}{8}$

Does 62 look like a fraction?

$62 = \dfrac {62}{1} = \dfrac{124}{2} = \dots \\ \mathbb{Z} \subset \mathbb{Q} \\ \text{so yes 62 is a "fraction", more accurately a rational number}\\ \text{it also happens to be a completely wrong answer in this context but that's another story}$