In the diagram, ¯CX bisects ∠ACB. Find the ratio of the area of triangle BCX to the area of triangle ACX. Express your answer as a common fraction.
Since CX is an angle bisector
AX / AC = BX / BC
AX /10 = BX / 10
AX / BX = 10 / 10
AX / BX = 1 / 1
So triangle ACX and BCX have the same bases...and they are under the sameheight
So the ratios of their areas = 1/1
+818 
