+1932 Triangle ABC has vertices A(2,3), B(1,−8) and C(−3,2). The line containing the altitude through A intersects the point (0,y). What is the value of y?
+130491 We can find an equation of the line through B and C
The slope of this line is [ 2 - - 8 ] / [ -3 -1 ] = 10 / -4 = -5/2
The equation of the line through A will have a negative reciprocal slope = 2/5
So.....the equation of this line is
y = (2/5)(x-2) + 3
y = (2/5)x - 4/5 + 3
y = (2/5)x +11/5
When x = 0 , y = 11/5 = 2.2
