help plz

Find positive integers a,b and c such that
$\dfrac{3}{11} = \frac {1} {a+ \frac1{b+ \frac1c}}$.

$\begin{array}{|r|rcl|rcl|} \hline \dfrac{3}{11} = \frac {1} {a+ \frac1{b+ \frac1c}} &\dfrac{11}{3} &=& a+ \frac1{b+ \frac1c} \\\\ &{\color{red}3}+\dfrac{2}{3} &=& {\color{red}a}+ \frac1{b+ \frac1c}~\Rightarrow \mathbf{a=3} \\\\ &\dfrac{2}{3} &=& \frac1{b+ \frac1c} &\dfrac{3}{2} &=& b+ \frac1c \\\\ &&&&{\color{red}1}+\dfrac{1}{2} &=& {\color{red}b}+ \frac1c ~\Rightarrow \mathbf{b=1} \\\\ &&&&\dfrac{1}{2} &=& \dfrac1c \\\\ &&&& \mathbf{2} &=& \mathbf{c} \\ \hline \end{array}$

$\dfrac{3}{11} = \frac {1} {3+ \frac1{1+ \frac12}}.$